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Cable tray bend formulas: 90, 45 and any angle

All the maths the calculator uses, for a 90 degree bend, a 45, or anything in between. The formulas are simple — a phone calculator is enough. Below: where they come from, worked examples, and a one-page cheat sheet you can print or save as a PDF in one tap — no sign-up.

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Where the cut-out formula comes from

When tray is bent, the outer edge keeps its length while the inner edge has to get shorter — otherwise the metal has nowhere to go. That difference is the cut. Geometrically, a wedge whose apex angle equals the turn angle sits on the tray width: half the opening is to the width as the tangent of half the angle. That gives the main formula.

Why the angle is halved

The wedge is symmetrical about the bend line: half goes left, half goes right. Each half is a right triangle with one leg equal to the tray width and an angle equal to half the turn. The tangent of that angle gives the other leg — the cut on one side.

The allowance on offsets

For an offset, the spacing between notches is not the plain diagonal. Each notch removes a wedge, and as it folds the bend line draws inward by exactly one cut. So the cut is added to the diagonal — otherwise the second turn lands short and the run never reaches the line you planned.

Symbols

W
tray width, mm
H
side height, mm
θ
turn or bend angle, degrees
L
cut each way from the bend line, mm
O
sideways offset, mm
ΔH
change in height, mm
R
arc radius at the centre of the run, mm
n
number of notches on the arc

Horizontal turn

L = W · tan(θ/2)

Cut in the base, each way from the bend line. Full opening is 2L.

300 mm tray at 45°: L = 300 · tan(22.5°) = 300 · 0.4142 = 124 mm

Vertical bend

L = H · tan(θ/2)

Same again, but the side height sets the size. Both sides are cut.

60 mm side at 45°: L = 60 · 0.4142 = 25 mm

Sideways offset

D = O / sin θ, centre to centre = D + L

D is the diagonal. The cut is added to it as the allowance for removed metal.

250 mm offset at 45° on 300 mm tray: D = 250 / 0.7071 = 354 mm, centres 354 + 124 = 478 mm

Change between levels

Sloped length = ΔH / sin θ

The horizontal reach is ΔH / tan θ.

250 mm rise at 45°: length = 250 / 0.7071 = 354 mm

Arc from segments

θ = Φ / n, L = W · tan(θ/2), pitch = 2 · (R + W/2) · sin(θ/2)

Φ is the full arc angle. Deviation from a true circle: (R + W/2) · (1 − cos(θ/2)).

Ø2000, 300 mm tray, 90° in 6 notches: θ = 15°, L = 39 mm, pitch = 300 mm, deviation 10 mm

Tangent of half the angle — for working it out by hand

Multiply the tray width by the number from the table to get the cut on one side.

Angletan(θ/2)100200300400
15°0.131713263953
22.5°0.198920406080
30°0.2679275480107
45°0.41424183124166
60°0.577458115173231
90°1.0000100200300400
Download the cheat sheet (PDF)One A4 page: every formula, worked examples and a size table. Free, no sign-up.
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